What is the force the string exerts on the stopper? - what is methacone
A rubber stopper 0.150 kilograms at the end of the chain attached with 1.00 m and swings in a circle.
If the upper limit 0.85 U / s, is what carries the force of the rope on the CAP?
Sunday, January 31, 2010
What Is Methacone What Is The Force The String Exerts On The Stopper?
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2 comments:
Ok, so it could be very wrong about this, but here's what I get as an answer.
V = 2 (PI) (R) (f)
V = 2 (PI) (1m) (85 U / s)
V = 5.340707511
A = (V ^ 2) / r
A = ((5.340707511) ^ 2) / 1
A = 28.52315672
F = ma
F = (.15 kg) (28.52315672)
F = 4.278473508 N
F is the force
One is the acceleration
M is the mass
V is the velocity
Pi is 3.141592 .......
r is the radius
f is the frequency
I apologize if this is wrong and I wasted your time haha.
HyperPhysics.info recommended for all and all problems in physics.
A quick search of the centripetal acceleration is obtained:
http://hyperphysics.info/?cx=partner-pub ...
The first link contains descriptions, images, equations, and even a simulator online!
Enjoy!
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